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schepotkina [342]
3 years ago
8

A less massive moving object has an elastic collision with a more massive object that is not moving. Compare the initial velocit

y of the less massive object to it's final velocity
Physics
1 answer:
stepladder [879]3 years ago
7 0

Assume that the small-massed particle is m and the heavier mass particle is M.

Now, by momentum conservation and energy conservation:

   mv = mv_{m} + Mv_{M}

   mv^{2} = mv^{2}_{m} + Mv^{2}_{M}

Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

   v_{m} = v\frac{m - M}{m + M}\\\\\\v_{M} = v\frac{m + M}{m + M}\\

So now, we see that v_{m} < 0 and v_{M} > 0. So therefore, the smaller mass recoils out.

Hope this helps you!

Bye!

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What is the gravitational force that two objects would feel if they are 3.5 meters apart? Object 1 has a mass of 10x10^5 kg and
polet [3.4K]

Answer:

1.63 N

Explanation:

F = GMm/r^2

  = (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2

  = 1.63 N  ( 3 sig. fig.)

6 0
3 years ago
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
dedylja [7]
The velocity is dueuueue. 100
8 0
3 years ago
What conventions are used in SI to indicate units
klemol [59]

Answer:

<u>Conventions used in SI to indicate units are as follows:</u>

  • Only singular form of units are used. for example: use kg and not kgs.
  • Do not use full stop after the abbreviations of any unit. for example: do not use kg. or cm.
  • Use one space between last numeric digit and SI unit. for example: 10 cm, 9 km.
  • Symbols and words should not be mixed. for example: use Kilogram per cubic and not kilogram/m3.
  • While writing numerals, only the symbols of the units should be written. for example: use 10 cm and not Ten cm.
  • Units named after a scientist should be written in small letters. for example: newton, henry.
  • Degree sign should not be used when the kelvin unit is used. for exmaple: use 37° and not 37°k

5 0
3 years ago
5. What is the velocity of a Nolan Catholic football player if he runs 200.0 m in 24.0 s?
Degger [83]

Answer:

\boxed{ \bold{ \huge{ \boxed {\sf{8.33 \: m \:/s \: }}}}}

Explanation:

Distance travelled = 200 metre

Time taken = 24 second

Velocity = ?

<u>Finding </u><u>the</u><u> </u><u>velocity</u><u> </u>

\boxed{ \sf{velocity =  \frac{distance \: travelled \: }{time \: taken}}}

\dashrightarrow{ \sf{velocity =  \frac{200 \: m}{24 \: s} }}

\dashrightarrow{ \sf{velocity = 8.33 \: m/s}}

Hope I helped!

Best regards!

6 0
3 years ago
how much gravitational potential energy do you give a 70 kg person when you lift him up 3 m in the air?
SCORPION-xisa [38]

Given gravitational potential energy when he's lifted is 2058 J.

Kinetic energy is transferred to the person.

Amount of kinetic energy the person has is -2058 J

velocity of person = 7.67 m/s².

<h3>Explanation:</h3>

Given:

Weight of person = 70 kg

Lifted height = 3 m

1. Gravitational potential energy of a lifted person is equal to the work done.

PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J

Gravitational potential energy is equal to 2058 Joules.

2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = -PE_g = -2058\ kg.m/s^2

Kinetic energy gained by the person = (-2058 kg.m/s²)

4. Velocity = ?

Kinetic energy magnitude= \frac{1}{2} m\times v^2 = m\times g \times h

Solving for v, we get

v=\sqrt{2gh} =\sqrt{2\times 9.8 \times 3} = \sqrt{58.8} = 7.67 m/s^2

The person will be going at a speed of 7.67 m/s².

4 0
3 years ago
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