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KengaRu [80]
3 years ago
6

What are the domain and range of the function f(x)= 1/4(x^3+6^2+5x-4)

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0

Answer:

it is 300

Step-by-step explanation:

because of you get it and dived it den you will time it so you will get to 300

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Cara started working for $9 per hour. She earns a 4% raise every year. What is her
shutvik [7]

Answer:

Caras hourly wage is $10.08 after 3 years

Step-by-step explanation:

4% of 9

0.04 x 9 = 0.36

then you multiply 0.36 by 3 because you are solving for 3 years.

0.36 x 3 = 1.08

then you add 1.08 to 9 because Cara's wage goes up $1.08 in 3 years

1.08 + 9 = 10.08

answer:

Cara's hourly wage is $10.08 after 3 years of working

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3 years ago
What is the unit rate for 2,500 kilobytes in 5 minutes
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2500/5=500 this is the unit rate

8 0
3 years ago
The sum of two numbers is 78. One number is 28 more than the other. Find the numbers
Sloan [31]
It is 54 I think idk I’m just trying to get started lol.
3 0
3 years ago
Read 2 more answers
Which set represents the domain of the function shown? (5 points)
Vikentia [17]

Answer:

To make it simple, when finding the domain all you have to do is look for the x within the points.

Looking at the first set you can tell that the domain is -3, 0, 4, and 11

The y or the f(x) would be 6, 2, 7, and 15

(Just saying y and f(x) are the same thing.)

For the next set the domain is 6, 2, 7, and 15

For the f(x) it is -3, 0, 4, and 11

Remeber x and Domain is the same thing so all you have to do is look for the x within the points of the plot, as for looking for the range, it is the same thing as y or f(x).

God Bless

Hope that this helps!!!!!!!!!!!!!!

7 0
3 years ago
Read 2 more answers
What are the solutions of 3d-<-10or 2d+7>9?
Natali5045456 [20]

3d < -10\ \vee\ 2d+7 > 9\\\\(1)\qquad3d < -10\ \ \ \ |:3\\.\qquad \qquad d < -\dfrac{10}{3}\\\\(2)\qquad2d+7 > 9\ \ \ \ |-7\\.\qquad\qquad2d > 2\ \ \ \ |:2\\.\qquad\qquad d > 1\\\\Answer:\ d < -\dfrac{10}{3}\ \vee\ d > 1\to d\in\left(-\infty,\ -\dfrac{10}{3}\right)\ \cup\ (1,\ \infty)

3 0
3 years ago
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