Answer:
u as the subject of the given formula is, 
Step-by-step explanation:
Given;
v² = u²+2as
To make u the subject of the formula, the following steps are taken;
v² = u²+2as
v² - 2as = u²
take the square - root of both sides of the equation;

Thus, u as the subject of the given formula is, 
Answer:
g(x) = |x/5|
Step-by-step explanation:
A function is stretched horizontally by a factor of k when x is replaced by x/k.
g(x) = f(x/5)
g(x) = |x/5| . . . . . stretch of absolute value by a factor of 5
To be honest I don’t know but I just looked up diameter and I think the second one pan is right please understand I’m in sixth grade
The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with:

Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.
Answer:
Combine Like terms and do the Equation normally
Step-by-step explanation: