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Lelu [443]
3 years ago
5

What is the approximate frequency of a photon having an energy 3.2 * 10^-24 J? (h = 6.6*10^-34 J*s)

Chemistry
1 answer:
hichkok12 [17]3 years ago
4 0

The Planck’s Equation states that

E = hv

E stands for energy measured in Joules

v stands for frequency measured in s^-1 or Hertz (Hz)- 1Hz .

h is Planck’s constant which is equivalent to 6.626x10-34 J.s


The Planck's equation states that the energy of a photon, is directly proportional to its frequency (v), by a constant factor (h).


Given:

E=3.2 * 10^-24 J

h= 6.626x10-34 J.s

Now we know that

E=hv

Thus substituting the given values we get

v=3.2 * 10^-24 /6.626x10-34

v=48 x 10^9 s^-1

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Answer:

<h3>The answer is 0.34 g/mL</h3>

Explanation:

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density =  \frac{mass}{volume}  \\

From the question we have

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<h3>0.34 g/mL</h3>

Hope this helps you

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When compounds possess a plane of symmetry between the chiral centers they are called achiral or meso compounds. Among the given compounds (A) compound 1 have a plane of symmetry. So we can say compound one is a meso or achiral compound. Compounds two, three, and four have no plane of symmetry, as you can see in the structures attached. So all other compounds (compound 2, compound 3, and compound 4) except compound one are not meso or achiral.

You can also learn about meso compounds from the following question:

brainly.com/question/29022658

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