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astraxan [27]
4 years ago
7

Mg(s) + ½O2(g) → MgO(s) + 146 kcal/mole H2(g) + ½O2(g) → H2O(g), ΔH = -57.82 kcal/mole What type of reaction is represented by t

he previous two examples?
Chemistry
1 answer:
adell [148]4 years ago
7 0
Answer is: both reactions are exothermic.

<span>In exothermic reactions, heat is released and enthalpy of reaction is less than zero (as it show second chemical reaction).
According to Le Chatelier's principle when the reaction is <span>exothermic heat is included as a product (as it show first chemical reaction).</span></span>
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Which of the following is the balanced equation for P + O2 → P2O5? Question 3 options: A) 4P + O2 → 2P2O B) P + 5O2 → 2P2O5 C) 4
Luden [163]

Given equation:

P + O2 → P2O5

In order for the equation to be balanced, the stoichiometry of the atoms of one kind on the reactant side must be equal to that on the product

Reactants                                            Products

P = 1                                                       P = 2

O = 2                                                     O = 5

The balanced equation would be:

4P + 5O2 → 2P2O5

Reactants                                            Products

P = 4                                                      P = 4

O = 10                                                    O = 10

Ans: D)


4 0
3 years ago
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Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3
maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

<em>H₂O = 516g</em>

<em>F⁻ = 0.163g</em>

<em>H₃O⁺ = 0.110g</em>

<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
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