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shepuryov [24]
3 years ago
12

How was the noble gas argon discovered

Chemistry
2 answers:
Serhud [2]3 years ago
8 0
Argon was discovered by sir William Ramsey,a Scottish chemist,and lord rayleigh,an English chemist,in 1894. argon makes up 0.93%of the the earth atmosphere making it the third more abundant gas.argon is obtained from the air as a by product of the production of oxygen and nitrogen.
Mashcka [7]3 years ago
4 0
Argon was discovered by Lord Rayleigh and Sir William Ramsay in 1894. It was isolated by examination of the residue obtained by removing nitrogen, oxygen, carbon dioxide, and water from clean air.
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4. What is a renewable resource? List some examples.
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Answer:

Renewable resources include biomass energy (such as ethanol), hydropower, geothermal power, wind energy, and solar energy. Biomass refers to organic material from plants or animals. This includes wood, sewage, and ethanol (which comes from corn or other plants).

five examples of renewable resources

Solar energy.

Wind energy.

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Bioenergy.

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Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
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belka [17]
The answer is 268.1 u....
5 0
3 years ago
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The 1995 Nobel Prize in chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th
Nikolay [14]

Answer:

\Delta H_{rxn3}=-162.5 kJ/mol

Explanation:

The reaction we need to calculate:

O_3 (g) + Cl (g) \longrightarrow ClO (g) + O_2 (g)

1) O_3 (g) + ClO (g) \longrightarrow Cl (g) +2 O_2 (g)

\Delta H_{rxn}=-122.8 kJ/mol

We need the ClO in the products side, so we use the inverse of this reaction:

Cl (g) +2 O_2 (g) \longrightarrow O_3 (g) + ClO (g)

\Delta H_{rxn1}=122.8 kJ/mol

2) 2 O_3 (g) \longrightarrow 3 O_2 (g)

\Delta H_{rxn2}=-285.3 kJ/mol

Now we need to combine this two:

Cl (g) +2 O_2 (g) + 2 O_3 (g)\longrightarrow O_3 (g) + ClO (g) + 3 O_2 (g)

Cl (g) + O_3 (g)\longrightarrow ClO (g) + O_2 (g)

The enthalpy of reaction:

\Delta H_{rxn3}=\Delta H_{rxn1}+ \Delta H_{rxn2}=122.8 kJ/mol-285.3 kJ/mol

\Delta H_{rxn3}=-162.5 kJ/mol

4 0
3 years ago
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