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2 years ago

Help with this algebra problem? 12y+6=6y+12?

1 answer:

7 0

First, combine like terms.
12y+6=6y+12 turns into
12y-6y=12-6, which is
6y=6. Now divide both sides by 6.
y=1

now do a quick check (cause that's always a good idea).
12(1)+6=6(1)+12
12+6=6+12
18=18 ; )

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Line p has an equation of y=-8x+6. Line q, which is perpendicular to line p, includes the point (2,–2). What is the equation of

Arturiano [62]

Answer:

$y = \frac{1}{8} x - 2 \frac{1}{4}$

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept

Line p: y= -8x +6

slope= -8

The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.

m(-8)= -1

m= -1 ÷(-8)

m= ⅛

Substitute m= ⅛ into the equation:

y= ⅛x +c

To find the value of c, substitute a pair of coordinates that the line passes through into the equation.

When x= 2, y= -2,

-2= ⅛(2) +c

$- 2 = \frac{1}{4} + c$

$c = - 2 - \frac{1}{4}$

$c = - 2 \frac{1}{4}$

Thus, the equation of line q is $y = \frac{1}{8} x - 2 \frac{1}{4}$ .

4 0

2 years ago

Help!!!!!!!!!!!!!!!!!!!

Vika [28.1K]

Answer:

base

median

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6 0

2 years ago

Which percent is equivalent to 0.3? A. 0.003% B. 0.03% C. 3% D. 30%

Kitty [74]

Answer:

D, 30%

Step-by-step explanation:

you move the decimal point twice to the right

8 0

2 years ago

Read 2 more answers

Justin is on a road trip. Over the past two days, he’s driven a total distance of 504 miles at an average speed of 56 miles/hour

irakobra [83]

Recall d = rt, distance = rate * time.

now, he has a speed rate of 56 mph for a distance of 504

$\bf d=rt\implies 504=56t\implies \cfrac{504}{56}=t\implies \stackrel{hours}{9}=t$

so, at that speed the whole driving time is 9 hours then. Ok, he drove 2 hours today, that means he drove 7 yesterday, 9 - 2.

how many miles is it for 7 hours at 56mph? d = rt ---> d = 56 * 7

that many miles he drove yesterday.

8 0

2 years ago

Graph: y - 10 = -2(z – 10)

ZanzabumX [31]

Slope = -2; y-intercept = 30

points: (2, 26); (3, 24)

3 0

3 years ago