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3 years ago

Help with this algebra problem? 12y+6=6y+12?

1 answer:

7 0

First, combine like terms.
12y+6=6y+12 turns into
12y-6y=12-6, which is
6y=6. Now divide both sides by 6.
y=1

now do a quick check (cause that's always a good idea).
12(1)+6=6(1)+12
12+6=6+12
18=18 ; )

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The floor plan shows an l shaped room. Shane wants to buy carpet for the room. The cost for one square foot of carpet is $4. Wha

VashaNatasha [74]

The area of shape is the amount of space on it.

The cost to carpet the room is $224

From the floor plan (see attachment), we can divide the room into two shapes:

A 8ft by 6ft rectangle
A 4ft by 2ft rectangle

So, the area of the floor plan is:

$\mathbf{Area = 8ft \times 6ft + 4ft \times 2ft}$

$\mathbf{Area = 48ft^2 + 8ft^2}$

$\mathbf{Area = 56ft^2}$

The unit cost of carpet is $4 per one square foot

So, the cost to carpet the room is:

$\mathbf{Cost = \$4 \times 56}$

$\mathbf{Cost = \$224}$

Hence, the cost to carpet the room is $224

Read more about cost functions at:

brainly.com/question/16860730

5 0

2 years ago

Different types of angels

marshall27 [118]

Step-by-step explanation:

assuming you are looking for angles and not angels:

Zero Angle (0° in Measure)

Acute Angle (0 to 90° in Measure)

Right Angle (90° in Measure)

Obtuse Angle (90 to 180° in Measure)

Straight Angle (180° in Measure)

Reflex Angle (180 to 360° in Measure)

Complete Angle (360° in Measure)

7 0

2 years ago

Choose the HCF of 6xy^3 and 9x^2y

snow_tiger [21]

Answer:

3xy

Step-by-step explanation:

$6x {y}^{3} = 2 \times 3 \times x \times y \times y \times y \\ 9 {x}^{2} y = 3 \times 3 \times x \times x \times y \\ \\ common \: factors = 3, \: x, \: y \\ \therefore \: HCF = 3\times x\times y\\\therefore \: HCF = 3xy \\$

8 0

3 years ago

What is the slope of the line shown

liubo4ka [24]

Answer: The Option is A, slope is -1/3

Step-by-step explanation:

4 0

3 years ago

Part 1 (Unit 2): Subtract Polynomials:

Alinara [238K]

Part 1
We have the following polynomials:
(3-6n5-8n4)
(-6n4-3n-8n5)
Subtracting the polynomials we have:
(3-6n5-8n4) - (- 6n4-3n-8n5)
n5 (-6 + 8) + n4 (-8 + 6) + 3n + 3
Rewriting:
2n5 - 2n4 + 3n + 3

Part 2
For this case we have the following polynomial:
4x2-2x-5 = 0
Using resolver we have:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
x = (- (- 2) +/- root ((- 2) ^ 2 - 4 * 4 * (- 5))) / (2 * 4)
x = (2 +/- root (4 + 80)) / (8)
x = (2 +/- root (84)) / (8)
x = (2 +/- root (4 * 21)) / (8)
x = (2 +/- 2raiz (21)) / (8)
x = (1 +/- root (21)) / (4)
The roots are:
x1 = (1 + root (21)) / (4)
x2 = (1 - root (21)) / (4)

8 0

3 years ago