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Lunna [17]
3 years ago
15

Plz answer this asap

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

50%

Step-by-step explanation:

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Show that an implicit solution of 2x sin2(y) dx - (x2 + 11) cos(y) dy = 0 is given by ln(x2 + 11) + csc(y) = C.
Dvinal [7]

Answer:

From the question we are told that

  The  equation is  2x sin^2(y) dx - (x^2 + 11) cos(y) dy = 0

Generally the goal of this solution is to prove that the implicit solution of the differential  equation above is  ln(x^2 + 11) + csc(y) = C.

First Step  

    Differentiate the solution with respect to  x  

   0  = \frac{2x}{ x^2 + 11}  + [-cot * csc(y) ]\frac{dy}{dx}

=> 0 =  \frac{2x}{ x^2 + 11}  + [-\frac{cos(y)}{ sin(y) }* \frac{1}{sin(y)}  ]\frac{dy}{dx}  

=>  0  =  \frac{2x}{ x^2 + 11}  + [-\frac{cos(y)}{ sin^2(y) }]\frac{dy}{dx}

=>  

multiply through by  sin^2(y) , x^2 + 11, dx

So

=> 2 x (sin^2(y) dx  + [-cos(y) (x^2 + 11)]dy = 0

Looking at the equation obtained we see that it is equivalent to the differential  equation hence  the implicit solution of 2x sin^2(y) dx - (x^2 + 11) cos(y) dy = 0 is   ln(x^2 + 11) + csc(y) = C.

Step-by-step explanation:

     

3 0
3 years ago
-x + 3y = 3 <br><br>x - 3y = 3<br><br>Does this system have a solution?
DerKrebs [107]

Answer:

No solution

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write out systems of equations

-x + 3y = 3

x - 3y = 3

Step 2: Rewrite equations into slope-intercept form

3y = 3 + x

y = 1 + x/3

-3y = 3 - x

y = -1 + x/3

Step 3: Rewrite systems of equations

y = x/3 + 1

y = x/3 - 1

Since we have the same slope for both equations but different y-intercepts, we know that both lines are parallel. If that is the case, they will never touch or intersect each other. Therefore, we have no solution.

4 0
3 years ago
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