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In the above figure, m&angle;P = 125° and m&angle;Q = 5x. If angles P and Q are supplementary angles.

Veseljchak [2.6K]

9514 1404 393

Answer:

the correct choice is marked: x = 11; Q = 55°

Step-by-step explanation:

If P and Q are supplementary, then ...

Q = 180° -P

Q = 180° -125°

Q = 55°

Then we have ...

5x = 55°

x = 11°

4 0

2 years ago

a spinner has three unequal sections: red, yellow, and blue. the table shows the results of nolan’s spins (red:10, yellow:14, bl

zubka84 [21]

A spinner has three unequal sections.

Red = 10

Yellow = 14

Blue = 6

$Total\: sections=Red+Yellow+Blue=10+14+6=30$

We are asked to find the experimental probability of landing on yellow.

Recall that the experimental probability is given by

$P=\frac{\text{number of desired outcomes}}{\text{total number of possible outcomes}}$

In this case, the number of desired outcomes are

Yellow = 14

The total number of possible outcomes is

Total sections = 30

$P=\frac{14}{30}=\frac{7}{15}$

Therefore, the experimental probability of landing on yellow is 7/15

7 0

8 months ago

Mr. Garret has a total of 20 students in his class. The number of female students is 4 less than twice the number of male studen

Serjik [45]

Answer:

8 male, 12 female

Step-by-step explanation:

male = x

female = 2x - 4

2x - 4 + x = 20

3x - 4 = 20

3x = 24

x = 8

2(8) - 4 = 12

there are 8 male, 12 female

5 0

1 year ago

7. The rectangle below is dilated by a scale factor of

tino4ka555 [31]

Answer:

i dont know

Step-by-step explanation:

i dont know

5 0

2 years ago

How do you solve this problem

Kryger [21]

Answer:

$sin(A) = \frac{21}{{29} }$

$cos(A)=\frac{20}{29 }$

$tan(A)=\frac{21}{20}$

$sin(C) = \frac{20}{{29} }$

$cos(C)=\frac{21}{29 }$

$tan(C)=\frac{20}{21}$

Step-by-step explanation:

So first we need to make sure we know the trig identities to solve this problem.

$sin(\alpha )=\frac{opposite}{hypotenuse}$
$cos(\alpha )=\frac{adjacent}{hypotenuse}$
$tan(\alpha )=\frac{opposite}{adjacent}$

Here we only have two legs of the triangle, so we will need to use the Pythagorean Theorem a² + b² = c² to solve for the missing leg, the hypotenuse in this case.

Solving for the hypotenuse, c, we get $c = \sqrt{a^{2} +b^{2} }$
Here a = 20 and b = 21, so plugging in these values to the equation we get: $c= \sqrt{(20)^{2}+(21)^{2} } =\sqrt{400+441} =\sqrt{841}=29$

Now we can use the trig identities to figure out the missing values for the problem

$sin(A) = \frac{21}{{29} }$
$cos(A)=\frac{20}{29 }$
$tan(A)=\frac{21}{20}$
$sin(C) = \frac{20}{{29} }$
$cos(C)=\frac{21}{29 }$
$tan(C)=\frac{20}{21}$

4 0

2 years ago