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3 years ago

Please help desperate trying to solve

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

The sequence needs to be rearranged so the negative numbers come before the positive. The correct sequence would be:
-9, -2, 0, 1, 3, 5

Andrew [12]3 years ago

7 0

You have to put the negatives first, because they are lower than the positives. All the student did was put them from least to greatest, and ignored the negatives, basically. This is correct: -9,-2, 0, 1, 3, and five

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zlopas [31]

Answer:

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General Formulas and Concepts:

Pre-Algebra

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Step-by-step explanation:

Step 1: Define expression

2(5m) + m

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2 years ago

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the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3>Solution:</h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

The formula for area of rectangle is given as:

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$

Hence length and width of rectangle is 15 inches and 6 inches.

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