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bezimeni [28]
3 years ago
6

Please help desperate trying to solve

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0
The sequence needs to be rearranged so the negative numbers come before the positive. The correct sequence would be:
-9, -2, 0, 1, 3, 5
Andrew [12]3 years ago
7 0
You have to put the negatives first, because they are lower than the positives. All the student did was put them from least to greatest, and ignored the negatives, basically. This is correct: -9,-2, 0, 1, 3, and five
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If our monthly income is $3050 in your house payment is $2400 what fraction of your monthly income must go to pay your house pay
ivolga24 [154]

Answer:

The 28% rule states that you should spend 28% or less of your monthly gross income on your mortgage payment (e.g. principal, interest, taxes and insurance). To determine how much you can afford using this rule, multiply your monthly gross income by 28%

6 0
2 years ago
State if the two triangles are similar and the rule that applies.
kobusy [5.1K]

Answer:

The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal and also, the angle formed by the two sides is equal. Side-Side-Side (SSS) rule: Two triangles are similar if all the corresponding three sides of the given triangles are in the same proportion.

Step-by-step explanation:

3 0
2 years ago
If the following fraction is reduced, what will be the exponent on the p? -5p^5q^4/ 8p^2q^2
viktelen [127]
<span>-5p^5q^4/ 8p^2q^2
= -5p^3q^2

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answer
</span><span>C.3</span>
6 0
3 years ago
Read 2 more answers
Use an induction proof to prove this statement:<br> For n≥1, 4^n+5 is divisible by 3.
Tpy6a [65]

Answer:

See below

Step-by-step explanation:

We shall prove that for all n\in\mathbb{N},3|(4^n+5). This tells us that 3 divides 4^n+5 with a remainder of zero.

If we let n=1, then we have 4^{1}+5=9, and evidently, 9|3.

Assume that 4^n+5 is divisible by 3 for n=k, k\in\mathbb{N}. Then, by this assumption, 3|(4^n+5)\Rightarrow4^k+5=3m,\: m\in\mathbb{Z}.

Now, let n=k+1. Then:

4^{k+1}+5=4^k\cdot4+5\\=4^k(3+1)+5\\=3\cdot4^k+4^k+5\\=3\cdot4^k+3m\\=3(4^k+m)

Since 3|(4^k+m), we may conclude, by the axiom of induction, that the property holds for all n\in\mathbb{N}.

3 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST
puteri [66]

Answer:

22.5

Step-by-step explanation:

You just have to do 60 divided by 2.66   (The decimal form of 2/3) and then you have your answer PLEASE BRAINLIEST

5 0
2 years ago
Read 2 more answers
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