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dimaraw [331]
3 years ago
14

Find (a) thr distance d(A,B) between the points A and B and (b) the midpoint of the segment AB

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

Answer:

x1 + x2 \div 2 \: y1 + y2 \div 2

Step-by-step explanation:

Answer is (4 , -1/2)

If you have any doubts see the image

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Mateo is constructing an equilateral triangle inscribed in a circle with center P. He draws the diameter of the circle through c
GenaCL600 [577]
Reading the question carefully, "<span>He draws the diameter of the circle through center P using a straight edge. Next he opens his compass to a width equivalent to the radius of the circle." - that implies that Mateo is still in the process of drawing the circle by which the equilateral is inscribed to.

The next steps should be:
*He should draw the upper and lower arcs using the compass opened to a width equivalent to the radius of the sircle.
*Make a vertical diameter using centroid P as basis.
*Draw two right triangles facing the opposite directions using the top most point by which the vertical diameter of the circle touches the top most circumference of the circle.

Doing these steps, Mateo will be able to draw an equilateral triangle inscribed in a circle.
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Please help asap. What is the missing statement and reason from the proof?
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According to the general equation for conditional probability,if p(a upside down u b)= 3/10 and p(b)=4/5 ,What is P(A|B)? A. 1/1
mash [69]
The correct answer for the question that is being presented above is this one: "A. (3/8)." According to the general equation for conditional probability if P(AupsidedownuB) = (3/10) and P(B)= (2/5), then P(A|B) is 3/8.Here are the following choices:A. (3/8)B. (1/2)C. (3/4)D. (1/16)

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A number a decreased by 7 is 2.
umka21 [38]

Answer:

9

Step-by-step explanation:

Let's first convert this to numbers. When a number is decreased by a certain amount, that is the same as saying that something is subtracted from it. Therefore:

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In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

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  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
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