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snow_tiger [21]
3 years ago
6

The quotient of a number and 8 is 16

Mathematics
2 answers:
enot [183]3 years ago
8 0
The quotient of 8 and 16 is 2
snow_lady [41]3 years ago
6 0
The quotient means that you are dividing and is means equals so the setup is:
x/8 = 16
x = 8 * 16 = 128
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Answer:

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Step-by-step explanation:

7 0
2 years ago
Which of the following ordered pairs
ozzi

The ordered pairs  that make this equation true is (4, 10)

A linear equation is given by:

y = mx + b;

where y, x are variables, m is the slope of the line and b is the y intercept.

Given the linear equation: y = 10x - 30:

At (1, -12): y = 10(1) - 30 = -20 ≠ -12

At (8, 1): y = 10(8) - 30 = 50 ≠ 1

At (4, 10): y = 10(4) - 30 = 10

At (6, 20): y = 10(6) - 30 = 30 ≠ 20

The ordered pairs  that make this equation true is (4, 10)

Find out more at: brainly.com/question/13911928

5 0
3 years ago
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insens350 [35]

Answer:

25

Step-by-step explanation:

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5 0
3 years ago
What is the slope of the line?<br><br>-2<br><br>1/2<br><br>1<br><br>2
photoshop1234 [79]
Going to be number two becaus
4 0
3 years ago
What is the equation of a line passing between the points below? (-3,1) (5,-7)
kirill [66]

Answer:

Ax + Ay + 2A = 0 for any nonzero A, for example (A=1): x + y + 2 = 0

Step-by-step explanation:

The equation of a line is

Ax + By + C = 0

so we know that:

A*-3 + B*1 + C = 0

A*5 + B*-7 + C = 0

Let's subtract one from the other:

A*(-3 - 5) + B*(1 + -7) = 0

A*-8 + B*8 = 0

B*8 = A*8

B = A

Let's input B = A into the first two equations

A*-3 + A*1 + C = A*-2 + C = 0

A*5 + A*-7 + C = A*-2 + C = 0

checks out

C = 2A

So for any nonzero A the equation of

Ax + Ay + 2A = 0 produces a line passing between the points. Example would be

x + y + 2 = 0

4 0
2 years ago
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