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Gekata [30.6K]
3 years ago
12

An accounting machine operator wanted to divide an 85-minute job between two identical machines so that one machine would take o

ne and a half times as long as the other. how much time (in minutes) was taken by the machine doing the longer job?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0
To find how much time the machine that took the longer job is, you would create an equation in terms of X, the amount of time it takes one of the machines.

Please see the attached picture for the work.

51 minutes is the longer time.
34 minutes for the other machine.

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If this fish tank is filled only halfway, how much water will it hold?
Morgarella [4.7K]

Answer:

I believe you typed your final answer choice incorrectly, as it should read 960 which is the correct answer

Step-by-step explanation:

the volume is 1920

1920/2=960

6 0
3 years ago
Explain why all squares are similar????? and please help with question below!!!!!!!!!!!!!
Oliga [24]
That's not a squre
anyway, we use ratios
base:person to corner=28:8
height to height=x:5
so
28/8=x/5 becasue same ratio
28/8=14/4=7/2
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17.5=x

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5 0
3 years ago
9(s)+3=57 what is dose the letter s represent in this quation
xz_007 [3.2K]
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3 0
3 years ago
I need help on this question
poizon [28]

Can you take picture better?I need to see this good

8 0
3 years ago
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
3 years ago
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