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Flauer [41]
3 years ago
15

Which equation is correct?

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0

Equation which is correct

792 × 5 = 700 × 5 + 90 × 5 + 2 × 5

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That is right points have no height width or any other value at all
6 0
4 years ago
Help please really need it fast :)
Serga [27]

Answer:

.4 x .9

Step-by-step explanation:

5 0
3 years ago
Circle the numbers that would make a square array
Artemon [7]

Hello from MrBillDoesMath!

Answer:   1, 4, 9. 16, 25, 36

Discussion:

If by "square array" you mean an array of perfect squares, the answer is


1, 4, 9. 16, 25, 36



Thank you,

MrB

4 0
3 years ago
Later 7 students joined group 2 (41 students)and one student left to join group 1. (44 students) Now 20 students play trombone a
Anit [1.1K]

48 students in group 2

43 students in group 1

So in total there are 91 students

7 students play the trump

And 20 play the trombone

Therefore it is known that 27 students play those two instruments in total

Because of this, Subtract 27 from 91 to get the num of students who doesn't play those instruments.

8 0
3 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
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