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3 years ago

6

Yolanda, Hong, and Ahmad served a total of 70 orders Monday at the school cafeteria. Yolanda served 6 fewer orders than Ahmad. H

ong served 2 times as
many orders as Ahmad. How many orders did they each serve?

1 answer:

irina [24]3 years ago

5 0

Answer:Yolanda served 13 orders.

Ahmad served 19 orders.

Hong served 38 orders.

Step-by-step explanation:

Let x represent the number of orders that Ahmad served.

Yolanda served 6 fewer orders than Ahmad. This means that the number of orders that Yolanda served is x - 6

Hong served 2 times as

many orders as Ahmad. This means that the number of orders that Hong served is 2x

Yolanda, Hong, and Ahmad served a total of 70 orders Monday at the school cafeteria. This means that

x - 6 + x + 2x = 70

4x - 6 = 70

4x = 70 + 6 = 76

x = 76/4 = 19

Hong served 2 × 19 = 38

Yolanda served 19 - 6 = 13

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Step-by-step explanation:

For this case we have the following info given:

A: 431, 447, 306, 413, 315, 432, 312, 387, 295, 327, 323, 296, 441, 312

B: $1.35, $1.82, $1.82, $2.72, $1.07, $1.86, $2.71, $2.61, $1.13, $1.20, $1.41

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$CV= \frac{s}{\bar X}$

Where the sample mean is given by:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

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$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

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We have the following results:

$\bar X_A = 359.786$

$s_A= 60.904$

$CV_A = \frac{60.904}{359.786}= 0.169 \approx 0.2$

Dataset B

We have the following results:

$\bar X_B = 1.791$

$s_B= 0.635$

$CV_B = \frac{0.635}{1.791}= 0.355 \approx 0.4$

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