Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F = 
where k= 
So , 2.2 = ( 
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
You have to divide and wants you divided add the 4 numbers that will give you your answers
Hi there!
»»————- ★ ————-««
I believe your answer is:
65% has the greater value.
»»————- ★ ————-««
Here’s why:
- We can convert both numbers into decimals and then compare the values.
⸻⸻⸻⸻
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
-----------------------
Find Slope :
-----------------------
3y = -4x + 2
y = -4/3x + 2/3
Slope = - 4/3
-----------------------
Answer: -4/3
-----------------------
(7 + 10) / 5 would be the expression
