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guapka [62]
2 years ago
14

What is the surface area for a rectangle with a length of seven a width of seven and a height of 11

Mathematics
1 answer:
Vilka [71]2 years ago
6 0
539 should be your answer. Not 100% sure.
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I need help Find the product.<br> 45 × 40
Crazy boy [7]
It’s is 1800

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6 0
3 years ago
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Help me with question b plz
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6 0
3 years ago
45% to a decimal ples help out
yan [13]

Answer:

45% = 0.45

Step-by-step explanation:

45%

= \frac{45}{100}

= 0.45

7 0
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Select the correct answer
Amiraneli [1.4K]

Answer:

c or d

Step-by-step explanation:

8 0
2 years ago
Answer ASAP, Will give brainliest
erastova [34]

Answer:

Step-by-step explanation:

1) ABCD is a trapezium. AB ║ CD

∠ADC + ∠DAB  = 180°  { Co interior angles}

110° + ∠DAB = 180

         ∠DAB = 180 -110

∠DAB = 70°

2) Sum of all angles of trapezium = 360°

∠A + ∠B + ∠DCB + ∠D = 360

70° + 50° + ∠DCB + 110° = 360

                 230 + ∠DCB = 360

                            ∠DCB = 360 - 230

∠DCB = 130°

3) For finding the height, use Pythagorean theorem

height² + base² = hypotenuse²

      height² + 6² = 10²

      height² + 36 =100

               height² = 100 - 36

              height² = 64

               height = √64

height = 8 m

4) a = AB = x m

  b = 9 m

h = height = 8 m

Area of trapezium = 120 m²

\frac{(a+b)*h}{2}\\\\  = 120

\frac{(x+9)*8}{2} =120\\\\\\(x +9)*4 = 120

x + 9 = 120/4

x + 9 = 30

    x = 30 - 9

x = 21 m

AB = 21m

                             

7 0
3 years ago
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