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ale4655 [162]
3 years ago
9

Let X be a random day of the week, coded so that Monday is 1, Tuesday is 2, etc. (so X takes values 1, 2,..., 7, with equal prob

abilities). Let Y be the next day after X (again represented as an integer between 1 and 7). Do X and Y have the same distribution
Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0

Answer:

Yes. Have the same distribution.

Step-by-step explanation:

Given that X is a random day of the week, coded so that Monday is 1, Tuesday is 2, etc. (so X takes values 1, 2,..., 7, with equal probabilities).

Y is the next day after X

So Y can be written as X+1

But since highest value is 7, we can write

Y = X+1 mod 7

i.e. whenever X=7, Y= 8= 1 again.

Thus Y can take values as

Y  1   2   3   4   5   6   7

P(Y) = P(X+1) = 1/7

i.e. Y also has the same distribution as X

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G(x) = -2x^3 – 15x^2 + 36x
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Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
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2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

3. The domain is x\in (-\infty,\infty), the range is y\in (-\infty,\infty).

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