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belka [17]
3 years ago
13

What is the perimeter 2x+3 as length and x-6 as width

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0

What is the perimeter 2x+3 as length and x-6 as width

P = 2L + 2W

P = 2(2x+3)+2(x-6)

P = 4x+6 + 2x - 12

P = 6x - 6

<h2>#CarryOnLearning</h2><h2>#LearningIsFun</h2>

Burka [1]3 years ago
4 0

Answer:

perimeter = 2(l + b) \\  = 2(2x + 3 + x - 6) \\  = 4x + 6 + 2x - 12 \\  = 6x - 6

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The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
5. Find the surface area of the cone. Round to<br> the nearest hundredth.<br> 2 ft<br> 6 ft
den301095 [7]

Answer:

52.3m^2

Step-by-step explanation:

Use these formulas

A=\pi rl+\pi r^2\\l=\sqrt{r^2+h^2}

Now solve

A=\pi r(r+\sqrt{h^2+r^2} )\\=\pi *2*(2\sqrt{6^2+2^2} )\\=52.3m^2

4 0
3 years ago
Someone took the elevator down 2 floors to the basement. would it be positive/negative?
kirill [66]

Answer:

Negative

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Fractions and integer operations practice, I need help please.
olga2289 [7]
40/11 = 3.63
hope this helps
3 0
3 years ago
Can you help please? It would be helpful.
steposvetlana [31]

Answer:

660 square feet

Step-by-step explanation:

1 chain = 66 feet

Length ( l ) = 66 feet

Breadth ( b ) = 10 feet

To find :

The area of a cricket pitch in square feet = ?

The area of a cricket pitch in square feet will be in the shape of rectangle.

Formula : -

Area of a rectangle = lb

Area of a rectangle

= 66 x 10

= 660 square feet

Therefore,

660 square feet is the area of a cricket pitch.

8 0
3 years ago
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