Question

The graph of y = 3 over the sqaure root of x

Answer 1

Answer:

$f(x) =\frac{3}{\sqrt{-x}}-2$

Observe the attached image

Step-by-step explanation:

The original function is:

$y =\frac{3}{\sqrt{x}}$

If we have a function g(x), then the graph of g(-x) will be equal to the graph of g(x) reflected on the y-axis.

In the same way, the graph of g(x)-2 is equal to the graph of g(x) displaced 2 units down

In this case $y = g(x)=\frac{3}{\sqrt{x}}$

Then

$g(-x) =\frac{3}{\sqrt{-x}}$

Finally

$f(x) =g(-x)-2 =\frac{3}{\sqrt{-x}}-2$

$f(x) =\frac{3}{\sqrt{-x}}-2$

The graph of f(x) is equal to the graph of $y =\frac{3}{\sqrt{x}}$ reflected on the axis-y and displaced 2 units downwards as seen in the attached image