Question

Electric field just outside a charged conductor is perpendicular to the surface and has a magnitude σ/2ε.

Answer 1

Answer:

The answer is False

Explanation:

For a infinite sheet of charges, the electric field is perpendicular to its surface. To calculate the electric field, we use a Gaussian surface (cylinder), getting that

$\Phi=E2A=\frac{\sigma A}{\epsilon_{0}}$

from where

$E=\frac{\sigma}{2\epsilon_{0}}$

Then the field calculated is one half of the field of a conductor charged with $\sigma$, this means that the magnitude of the charged conductor is

$E=\frac{\sigma}{\epsilon_{0}}$

Therefore the answer is False.