Answer:
The deceleration is 
Explanation:
From the question we are told that
The height above firefighter safety net is 
The length by which the net is stretched is 
From the law of energy conservation
Where 
is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )
and 
is the potential energy of the before jumping which is mathematically represented at
and 
is the kinetic energy of the person just before landing on the safety net which is mathematically represented at
and 
is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )
So the above equation becomes
=> 
substituting values
Applying the equation o motion
Now the final velocity is zero because the person comes to rest
So
-- A tornado follows a path that's a few miles wide, for a few hours.
Then it's all over.
-- A hurricane follows a path that's several hundred miles wide,
for a week or two, before it's over.
Then comes the rain, continuing on the same path, for another week.
Answer:
t = 0.55[sg]; v = 0.9[m/s]
Explanation:
In order to solve this problem we must establish the initial conditions with which we can work.
y = initial elevation = - 1.5 [m]
x = landing distance = 0.5 [m]
We set "y" with a negative value, as this height is below the table level.
in the following equation (vy)o is equal to zero because there is no velocity in the y component.
therefore:
![y = (v_{y})_{o}*t - \frac{1}{2} *g*t^{2}\\ where:\\(v_{y})_{o}=0[m/s]\\t = time [sg]\\g = gravity = 9.81[\frac{m}{s^{2}}]\\ -1.5 = 0*t -4.905*t^{2} \\t = \sqrt{\frac{1.5}{4.905} } \\t=0.55[s]](https://tex.z-dn.net/?f=y%20%3D%20%28v_%7By%7D%29_%7Bo%7D%2At%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2At%5E%7B2%7D%5C%5C%20%20%20where%3A%5C%5C%28v_%7By%7D%29_%7Bo%7D%3D0%5Bm%2Fs%5D%5C%5Ct%20%3D%20time%20%5Bsg%5D%5C%5Cg%20%3D%20gravity%20%3D%209.81%5B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%5D%5C%5C%20-1.5%20%3D%200%2At%20-4.905%2At%5E%7B2%7D%20%5C%5Ct%20%3D%20%5Csqrt%7B%5Cfrac%7B1.5%7D%7B4.905%7D%20%7D%20%5C%5Ct%3D0.55%5Bs%5D)
Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.
![(v_{x} )_{o} = \frac{x}{t} \\(v_{x} )_{o} = \frac{0.5}{0.55} \\(v_{x} )_{o} =0.9[m/s]](https://tex.z-dn.net/?f=%28v_%7Bx%7D%20%29_%7Bo%7D%20%3D%20%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5C%28v_%7Bx%7D%20%29_%7Bo%7D%20%3D%20%5Cfrac%7B0.5%7D%7B0.55%7D%20%5C%5C%28v_%7Bx%7D%20%29_%7Bo%7D%20%3D0.9%5Bm%2Fs%5D)
First we shall look at some terms:
Velocity - frequency of change of an objects position.
Acceleration - frequency of change of an objects velocity
Since velocity covers both change in direction and speed, we can asume that the answer is B, not because it's the only one we worked with, but because the others don't make any sense:
A - this is not correct, because a chnage in direction can be done withough a change in speed.
C - The scientific definition of acceleration does include speed, and this is not a reasonable answer.
D - Velocity can change, unlike said in the sentence.
Hope it helped,
BioTeacher101
Answer:
force of attraction will be increased by 9
Explanation:
force of attraction is inversely proportional to square of distance
i.e F= 1/R²
F=1/3R²
F=1/9R
9×F= 9×1/9R
9F= 1/R
so force of attraction is 9 times
