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3 years ago

Can someone please tell me the answer I am about to cry

Mathematics

2 answers:

hjlf3 years ago

7 0

A.
you can find the angle measures of the big triangle and then find it’s corresponding angle.

photoshop1234 [79]3 years ago

4 0

Answer:

a.) 80°

Step-by-step explanation:

Let's start with triangle VZY.

In angle V, you notice how two lines intersect there. and you notice the outer angle is 132°.

Imagine angle V is on a straight line of 180°, no triangles, just the line. Now you see there is a line that intersects the 180°, and on one side of the line is 132° but you need to solve for the missing side. You do this by setting up an equation of 132 + x =180 and then you will get your missing angle of 48°.

Now focus on the whole VZY triangle. You have 2 out of 3 angles (52° and 48°) and you need to solve for the last angle, Z.

You know a triangle adds up to 180°, so set up an equation like the one we did before and solve:

48+52+x= 180

100+x=180

x=80

A good rule of thumb is that whenever two lines intersect each other like they do at angle z, is that the opposite angles of each other are congruent to each other.

So where angle Z equals 80° on the first triangle, angle Z on the second triangle equals the same.

You might be interested in

What is the greatest possible product of a 2 digit number and a 1 digit number

Molodets [167]

891
because 99(the greatest 2 digit number)*9(the greatest 1 digit number)=891

3 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

1. Your average daily balance on your charge card for the month of July is $855.28. If your card carries an annual interest rate

Nat2105 [25]

1. Using "exact" interest, your charge will be
.. I = Prt
.. I = $855.28*0.154*(31/365)
.. I = $11.19

2. It will take 52.01 months to pay off the loan.

3. Your payment on 15,250 for 4 years will be $363.41. The effective interest rate that payment represents on a loan of $15,000 is 7.604%

4. Todd's monthly payments will be $409.06, so his total outlay will be
.. tax+license + down payment + loan repayment
.. = 1200 +1000 +48*409.06
.. ≈ $21,835