Answer:
468
Step-by-step explanation:
26 x 6 x3
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
These concepts become more clear when teachers use number disks instead of base ten blocks. Place value is a very important concept for elementary students because base ten is the foundation of our number system.
Answer:
9/4
Step-by-step explanation:
5×|-2-7(3)|-2×17
5×|-2-21|-34
5×|-23|-34
5×23-34
115-34=81
22+sq rt(7×28) 28=4×7 sq rt= 2×2×7×7
22+2×7=22+14=36
81÷9/36÷9=9/4
My apologies on answering late...
Same situation as the previous problem, but this time, all you need to do is state the degree of the angle instead of just providing the angle itself.
ΔABC ≅ ΔDEF
Now, we can see that ∠C ≅ ∠F. Using this information, we can find ∠C on the first triangle ( which is 
° ).
Since ∠C ≅ ∠F,
m∠F is °.
Hope I caught your question in time!
Have a good one! If you need anymore help, let me know.
