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jek_recluse [69]
3 years ago
10

If a rectangle is altered by increasing its length by 20 percent and its width by 10 percent, its area increases by a percent. W

hat is the value of a?
A) 25
B) 28
C) 30
D) 32
Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Remember that the formula for the area of a rectangle is:

A=lw

Where l is the our length and w is our width.

If we increase our length by 20%, this means that we add 20% or 0.2 of our old length to our old length. So, our new length will be:

l_{new}=l+.2l

Combine like terms:

l_{new}=1.2l

Similarly, if we increase our width by 10%, this means that we add 10% or 0.1 of our old width to our old width. So, our new width is:

w_{new}=0.1w+w

Combine like terms:

w_{new}=1.1w

Therefore, our new area will be:

A_{new}=(l_{new})(w_{new})

Substitute 1.2l and 1.1w. This yields:

A_{new}=1.2l(1.1w)

Multiply:

A_{new}=1.32lw

Our old area is:

A_{old}=lw

So, our area increased by a factor of 1.32.

This is the same as 32% of our old area.

So, our answer is D.

And we're done!

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Verizon [17]

Answer:

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Step-by-step explanation:

solution :

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b = 9 cm

we know ,

Area of parallelogram = b× h

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2 years ago
Help ASAP please! Thank you so much<br> What is the slope of the graphed line?
galina1969 [7]

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
To plot the point (5, -3) you would move up 5, then left 3.<br><br> True<br><br> False
frozen [14]

Hey there! :)

Answer:

False.

Step-by-step explanation:

In a point, the coordinates are in the format:

(x, y).

In this instance, x = 5 and y = -3. This means that to plot the point, you would need to:

Move right 5, down 3.

8 0
3 years ago
Read 2 more answers
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