4. x^10
5. x^3
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Complete the recursive formula of the geometric sequence -0.56\,,-5.6\,,-56\,,-560,...−0.56,−5.6,−56,−560,...Minus, 0, point, 56
pentagon [3]
Answer:
The recursive formula is:
Cn = 10C(n-1)
Step-by-step explanation:
Given the geometric sequence.
-0.56, -5.6, -56, -560, ...
The common ratio is
-5.6/-0.56 = -56/-5.6 = -560/-56 = ... = 10
The recursive formula is easily
Cn = C(n-1) × 10
That is a number is ten times the preceding number.
16: -7(5)= -35 ( REMEMBER THE MOUTH EATS THE BIGGEST NUMBER!)
-6(-6)= 36 therefore 36 is greater than -35
18: they are exactly the same because in multiplication with inters it matters when the signs change. so 3(-6) = -18 ad -3(6)= -18 then -18=-18
20: Same as 18 where division has the same rules. if 8x5=40 then 40/8=5
-40/8=-5 and 40/(-8)=-5 then -5=-5
answers:
Answer:
2.29 ft of side length and 1.14 height
Step-by-step explanation:
a) Volume V = x2h, where x is side of square base and h is hite.
Then surface area S = x2 + 4xh because box is open.
b) From V = x2h = 6 we have h = 6/x2.
Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.
We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.
Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.
To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.
And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2