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Minchanka [31]
3 years ago
10

Multiply 613 by the reciprocal of −716.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0
=613*-1/716
=-613/716
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The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc
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Answer:

\mu = 12.1\\\sigma = 0.3

a) Find the probability that the drink is less than 11.9 fluid ounces

We are supposed to find P(x<11.9)

x= 11.9

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z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

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b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces

x= 11.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.6-12.1}{0.3}

z=-1.67

x= 11.9

We will use z score formula :

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z=\frac{11.9-12.1}{0.3}

z=-0.67

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

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P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

P(-1.67<z<-0.67)= 0.2514-0.0475

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x= 12.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{12.6-12.1}{0.3}

z=1.67

Refer the z table

P(x>12.6)=1-P(x<12.6)

P(z>1.67)=1-P(z<1.67)

P(z>1.67)=1-0.9525

P(z>1.67)=0.0475

Hence  the probability that the drink is more than 12.6 fluid ounces is 0.0475

d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than  alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

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