1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IceJOKER [234]
3 years ago
15

Please help does anyone tutor or can like go dm me on Instagram so I can just ask a smart math person directly

Mathematics
1 answer:
Elis [28]3 years ago
6 0
I think c? i’m not sure
You might be interested in
Which of the following choices is equivalent to 1 + 8(2x + 3)?
RUDIKE [14]

Answer:

16x + 25

Step-by-step explanation:

First, distribute the 8 to both numbers within the parenthesis.

1 + 16x + 24

Then, add similar terms together.

16x + 25

8 0
3 years ago
To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52.) The orde
grandymaker [24]

Answer:  14,658,134,400

<u>Step-by-step explanation:</u>

There are 52 numbers to start with.  After choosing the first number, there are 51 numbers remaining, etc.

1st   and   2nd   and   3rd    and   4th  and   5th  and  6th

52    x       51       x      50      x       49    x      48     x     47  = 14,658,134,400

You can also find the answer using the following formula:

\dfrac{52!}{(52-6)!}=\dfrac{52!}{46!}=\dfrac{52\times 51\times 50\times 49\times 48\times 47 \times 46!}{46!}\\\\\\.\qquad \qquad \qquad \quad = 52\times 51\times 50\times 49\times 48\times 47\\ \\\\.\qquad \qquad \qquad \quad =\large\boxed{14,658,134,400}

6 0
3 years ago
Gina is making bags of trail mix for hiking club. She will use 20 ounces of walnuts, 11.2 ounces of almonds, and 28.3 ounces of
ser-zykov [4K]

Answer:

Step-by-step explanation:

20 oz walnuts = 20/25 = 0.8 ounces of walnuts per bag. / bag

11.2 oz of almonds = 11.2 / 25 = 0.448 ounces of almonds / bag

28.3 oz of cashews = 28.3 / 25 = 1.132 oz of cashews / bag

6 0
2 years ago
What will be the value of median of a moderately asymmetrical distribution? If the mean and mode are 30 and 24 respectively.
sineoko [7]

The mean, the median and the mode are measures of central tendency, and they are related in some many ways, depending on the type of distribution.

The median of the moderately asymmetrical distribution is 26

The given parameters are:

Mean = 30

Mode = 24

For a moderately asymmetrical distribution, the mean, median and mode are related by the following equation:

Mode = 3 * Median - 2 * Mean

Substitute known values

30= 3 * Median - 2 * 24

30= 3 * Median - 48

Collect like terms

3 * Median =30+ 48

3 * Median =78

Divide both sides by 3

Median =26

Read more at:

brainly.com/question/15669207

7 0
3 years ago
PLEASE HELP<br> Choose the equation that represents the graph below.
swat32

Answer:

i'd like to say that the correct answer is the one at the very bottom; y=x+3

7 0
4 years ago
Read 2 more answers
Other questions:
  • What is the value of 7 in:<br> a. 3.7<br> b. 12.07<br> c. 200.711
    13·1 answer
  • I live for walks at a rate of 4 mph she lives 2 miles from the news station how long will it take her to walk home from the news
    8·1 answer
  • Write an equation in point-slope form of the line that passes through (-2, -1) and has a slope of -3. Change the equation to slo
    14·1 answer
  • A garbage container is to be constructed out of 400 ft2 of material. The vessel will have a square base and an open top. Find th
    10·1 answer
  • How many terms are there in the following expression: 3a + 3ab + 7b – 4d?
    6·1 answer
  • Write an inequality for the following statement : "you have to be at least 18 years old to vote. "
    8·2 answers
  • Which expression is the best estimate for<br> 3 1/8 - 1 3/4?
    6·1 answer
  • What is 2 1/2 feet to inches?
    10·1 answer
  • Two similar triangles are shown
    6·2 answers
  • Determine forms of exponential expressions please help
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!