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MariettaO [177]
3 years ago
7

WILL AWARD BRAINLIEST AND BE YOUR BEST FRIEND AND 99 POINTS!!!!!!!!!!!

Mathematics
2 answers:
Doss [256]3 years ago
3 0

Answer:

P(55 good before first defective) = 80.66%, so take choice C, 81%.


Step-by-step explanation:

We want probability of 55 or more successes before a failure.

P(success) = 1 - P(failure)

= 1.0000 - 0.0039 = 0.9961

We assume the outcomes are independent.


P(55 successes with no failure) = 0.9961^55 = 0.80660647769



sweet [91]3 years ago
3 0

Answer:

P(success) = 1 - P(failure)

?  =  1.0000 - 0.0039 = 0.9961

P(55 successes with no failure) = 0.9961^55 = 0.80660647769

the answer is C 81%  (we rounded)

~batmans wife dun dun dun...

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