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3 years ago

11

Help me with my homework

1 answer:

kogti [31]3 years ago

3 0

Answer:

That is right

Step-by-step explanation:

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a standard 35-mm movie projects 24 images each second. at this rate, how many images are necessary for a 1.5 hour movie ?

yuradex [85]

129,600. 60 seconds in a minute, 60 minutes in an hour 60x60=3600, so 3600 seconds=1 hour. 1800 seconds = half hour. 3600 + 1800 = 5400 seconds in 1.5 hours. 5400 x 24 = 129,600. Hence, 129,000 images are necessary for a 1.5 hour movie.

Hope this helps!
Have a nice day :)
-fart2fart

3 0

3 years ago

At last year's company picnic, 25 pounds of ground beef were needed to make 100 hamburgers.How many pounds of ground beef will b

AVprozaik [17]

Answer:

30

Step-by-step explanation:

4 0

4 years ago

What is the surface area of a cylinder with a height of 12.9 and a radius of 9.2?

GalinKa [24]

The answer will be 1277.49

4 0

3 years ago

Convert the Cartesian equation x^2 + y^2 = 16 to a polar equation.

RideAnS [48]

Answer:

Problem 1: $r=4$

Problem 2: $r=-2\sin(\theta)$

Problem 3: $r\sin(\theta)=3$

Step-by-step explanation:

Problem 1:

So we are going to use the following to help us:

$x=r \cos(\theta)$

$y=r \sin(\theta)$

$\frac{y}{x}=\tan(\theta)$

So if we make those substitution into the first equation we get:

$x^2+y^2=16$

$(r\cos(\theta))^2+r\sin(\theta))^2=16$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)=16$

Factor the $r^2$ out:

$r^2(\cos^2(\theta)+\sin^2(\theta))=16$

The following is a Pythagorean Identity: $\cos^2(\theta)+\sin^2(\theta)=1$ .

We will apply this identity now:

$r^2=16$

This implies:

$r=4 \text{ or } r=-4$

We don't need both because both of include points with radius 4.

Problem 2:

$x^2+y^2+2y=0$

$(r\cos(\theta))^2+(r\sin(\theta))^2+2(r\sin(\theta))=0$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)+2r\sin(theta)=0$

Factoring out $r^2$ from first two terms:

$r^2(\cos^2(\theta)+\sin^2(\theta))+2r\sin(\theta)=0$

Apply the Pythagorean Identity I mentioned above from problem 1:

$r^2(1)+2r\sin(\theta)=0$

$r^2+2r\sin(\theta)=0$

or if we factor out r:

$r(r+2\sin(\theta))=0$

$r=0 \text{ or } r=-2\sin(\theta)$

r=0 is actually included in the other equation since when theta=0, r=0.

Problem 3:

$y=3$

$r\sin(\theta)=3$

8 0

4 years ago

Max's Market sells 6 eggs for £1.86.

Sav [38]

Answer:

fancy foodstuff .29 per eggs

Step-by-step explanation:

max's market .31 per eggs

galore .32 per eggs

fancy foodstuff .29 per eggs

3 0

3 years ago

Read 2 more answers