Find the area of the trapezoid. Leave your answer in simplest radical form.

Mathematics

1 answer:

murzikaleks [220]2 years ago

3 0

Answer:

The formula to find the area of a trapezoid is

A = (;a + b / 2 ) h

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The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length

Sophie [7]

Answer:

166

Step-by-step explanation:

So the width is 65, so two sides are each 65m long. So multiply 65*2 which is 130. this means that the other two sides need to equal 130 when added, so divide 130/2 which is 65

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Three investors own a company. One partner owns One-fourthof the company, while the second partner owns Two-fifths of the compan

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Answer:

7/20

Step-by-step explanation:

2/5 = 8/20

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Which of the following statements are true?

Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is false.

B. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is true.

C. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)}$ is translated 2 units to the right and vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of $\frac{1}{2}.$ . This option is true.

D. The function $f(x)=\dfrac{1}{2}\sqrt{x}$ has the domain and the range all non-negative real values. The function $f(x)=\sqrt[3]{x}$ has the domain and the range all real values. So this option is false.