A hat contains four balls. The balls are numbered 2, 4, 4, and 7. One ball is randomly selected and
1 answer:
Answer:
- If the sum is 6, a small cone will be ordered.
- If the sum is 8 or 9, a medium cone will be ordered.
- If the sum is 11, a large cone will be ordered.
Step-by-step explanation:
The table below shows the possible outcomes from drawing two balls. We see the relative frequencies to be ...
6: 4
8: 2
9: 2
11: 4
To make a fair decision, we want the relative frequencies of the decision possibilities to be the same. If we combine sums 8 and 9 to one category (medium cone, for example), then 6, (8 or 9), and 11 will all have the same relative frequency: 4.
The appropriate "fair decision" choice is ...
6: small cone
8 or 9: medium cone
11: large cone
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Answer:
yes
Step-by-step explanation:
There are several ways to go at this.
My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.
Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.
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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.
(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0
The value of h(5) is zero, so x-5 is a factor of h(x).
