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dangina [55]
3 years ago
5

Find a counterexample: Two sides of a

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer: Any isosceles triangle is a counter example. More specifically, a triangle with sides 7, 7 and 3

When forming your triangle, make sure you apply the triangle inequality theorem. This is the idea where adding any two sides leads to a result larger than the third side. So we have

7+7 = 14 which is larger than 3

7+3 = 10 which is larger than 7

By definition, an isosceles triangle has two congruent sides. Some books say "at least 2 congruent sides", but I'll go with the first definition. If you want all three sides to be congruent, then you'd go for the term "equilateral".

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The legs of a right triangle are 10 centimeters and 24 centimeters long what is the length of the hypotenuse ?
spayn [35]
Let the hypotenuse be x then,
Using the pythagoras theorm,
10^2 + 24^2 = x^2 (alt^2 + base^2 = hypo^2)
100 + 576 = x^2
676 = x^2
Therefore x= square root of 676 = 26
Hope this helped! :D
6 0
3 years ago
Please Help With This Problem
vladimir2022 [97]

the m will equal 10 because 1.2 times 10 equals 12

5 0
4 years ago
Read 2 more answers
 i will give brainliest for question 18 pts
kow [346]

Answer:

the answer is 20

Step-by-step explanation:

3 0
3 years ago
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Which equation does this image represent?
nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

Standard form of equation of ellipse:

$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1

where (h, k) is the center = (0,0)

a is the point on x-axis where y = 0. Hence a = 3.

b is the point on y-axis where x = 0. Hence b = 2.

Substitute this in the standard form of ellipse.

$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1

$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1

To make the denominator same multiply 1st term by \frac{4}{4} and 2nd term by \frac{9}{9}.

$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1

$\frac{4x^{2}}{36}+\frac{9y^{2}}{36}=1

$\frac{4x^{2}+9y^{2}}{36}=1

Multiply by 36 on both sides

$\frac{4x^{2}+9y^{2}}{36}\times 36=1\times 36

${4x^{2}+9y^{2}}={36}

The equation of the image is ${4x^{2}+9y^{2}}={36}.

8 0
4 years ago
Evaluate the expression for the given values.
Vlada [557]

Answer:

4ab8c

4(8)(4)(8(12)

(32)(38)(12)

(1216)(12)

14592

Step-by-step explanation:

7 0
3 years ago
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