-0.75-(-2/5) + 0.4 + (-3/4)
Simplify it :-)
-0.75 +

+ 0.4 -
Add the like terms / add your decimals with your decimals & your fractions with your fractions.
(-0.75 + 0.4) + (

-

)
Simplify :-)
0.35 + (
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-

)
Simplify :-)
0.35 + (-

)
Now you turn your decimal into a fraction.
0.35 = 35/100 = 7/50
NEW PROBLEM :

+

= ??
Make both denominators 100.

×

= 14 / 100
7/20 × 5/5 = 35/100
NEW PROBLEM :

+

=

:-)
Problem 2
Midpoint: Think 1/2. A midpoint cuts a line segment in 1/2 (in this question). That means that the left segment = the right segment. Remember: midpoint means 1/2.
LN is given as 14.
LM is 1/2 the distance of 14
LM = 1/2 * 14
LM = 7
Problem 3
If the midpoint = the 1/2 way point, the two halves are equal. Remember a midpoint divides the 2 parts into 2 EQUAL parts.
4a - 2 = 18 Add 2 to both sides
4a = 18 + 2
4a = 20
a = 20 /4
a = 5
Problem 4
Remember that midpoint means 1/2. That a midpoint cuts a segment into 2 equal segments
Equation
2n + 2 = 5n - 4
Solve
2n + 2 = 5n - 4 Add 4 to both sides
2n + 2 + 4 = 5n Subtract 2n from both sides.
6 = 5n - 2n
6 = 3n Divide both sides by 3
6/3 = n
n = 2
<u>Answer:</u> B
Problem 5
And again the whole line segment is divided into 2 equal parts.
<u>Equation</u>
6p - 12 = 4p Add 12 to both sides
6p = 12 + 4p Subtract 4p from both sides.
6p - 4p = 12
2p = 12 Divide by 2
p = 12/2
p = 6 <<<<< Answer
Answer:
46
Step-by-step explanation:
x=180-134=46
rate brainliest please
The answer chalk be d beach’s I think that if u divide the file into the adding h get the sndwbfjxurbrkxuf r du t do r can ur you. I I d ci t ci wait too y the. In the answer if the confindernt ox r FITB rxir cont the game so get better at the game
Answer:
0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability that a sophomore non-Chemistry major
Out of 92 students, 9 are non-chemistry major sophomores. So

Then a junior non-Chemistry major are chosen at random.
Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.