As for this problem of true or false, the most probable answer the most likely one to be the correct answer would be A. True.
In Microsoft Word, or commonly referred to as MS Word, or simply Word itself as what is utilized in the problem, the program has the ability to recognize in spelling and grammar. When a red wavy underline is present, the word or words above it are usually wrong in spelling. Though this can be corrected by the user by adding the word in the dictionary so as not to be corrected in the future. The green one would be more about grammar. The blue wavy underline would indicate a word spelled correctly, but might be misused in the sentence it belongs. This usually happens to words that are almost identical in spelling like too and to.
Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Answer:
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Explanation:
Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
