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Arada [10]
3 years ago
13

Technician A says that OBDI and OBDII use different DLC connectors. Technician B says that OBDII standardizes the designations f

or diagnostic trouble codes (DTCs). Who is correct? Technician A Technician B Both Technician A and Technician B Neither Technician A nor Technician B
Computers and Technology
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

The answer is "Technician B"

Explanation:

The OBDII is a standardized, automated framework which the USA EPA had approved and installed into its whole year of modeling (MY) 1996 and then into modern light-duty vehicles and trucks, recognized as "on-board diagnostics II."  

  • The DTC framework is a set of problematic diagnostic codes that used alert you if a vehicle is unable to operate using an on-board Diagnostic System.
  • If the system of the automobile identifies a problem, a special DTC code is generated as well as a position sensor is sent to the instrument cluster, that's why Technician B is correct.
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Software applications called _____ provide the means to record information that passes through a computer or router that is hand
Bezzdna [24]

Answer:

sniffer programs

Explanation:

Software applications called <u>sniffer programs</u>  provide the means to record information that passes through a computer or router that is handling Internet traffic.

3 0
3 years ago
The machine should not be oiled until the
kicyunya [14]
<span>The machine should not be oiled until the recommended time between oilings is up.</span>
6 0
3 years ago
Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a
kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = \frac{CPI*Instruction Count}{ClockRate}

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is =\frac{2.5*100,000}{750*10^6}

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =\frac{2.5*Instruction}{750*10^6}

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0
3 years ago
Which role is responsible for turning the product backlog into incremental pieces of functionality? bookmark this question
Misha Larkins [42]
The answer is the team. Teams are self-establishing which no one not even the scrum master tells the team how to turn product backlog into augmentations of stoppable functionality. Each team member put on his or her knowledge to all of the complications. The interaction that outcomes progresses the entire scrum team’s general competence and usefulness. The optimal size for a scrum team is seven people, plus or minus two. When there are fewer than five team members, there is less interface and as a result less productivity improvement. The product owner and scrum master roles are not comprised in this count. Team arrangement may variation at the end of a sprint. Every time Team membership is altered, the productivity increased from self-organization is reduced.
4 0
3 years ago
Read 2 more answers
16.50. Suppose we have a sequential (ordered) file of 100,000 records where each record is 240 bytes. Assume that B = 2,400 byte
Nat2105 [25]

Answer and Explanation:

Given that total number of records in a file = 100000

Each record consists of= 240 bytes

Given that B= 2400 bytes.

Then total blocks in file = 100000 records * 240 / 2400

= 10000 blocks.

Time that will take for exhaustive read

= s + r + b.btt

= 16 + 8.3 + (10000) * 0.8

= 8024.3 msec

Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.

Hence, X (s + r + btt) > 8024.3

X (16+8.3+0.8) > 8024.3

X > 8024.3/25.1

So that, X > 319.69

Hence, atleast 320 random reads should be made to search the file

8 0
3 years ago
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