Answer:
D. 25x24x23x22x21.....3x2x1.
Explanation:
The ceasar cipher is a encryption technique, that uses a combination of information or keys to encrypt an information.
The 25 shift ceasar cipher has 25 different combinations, so the number of probable random cipher substitution is 25!,
That is = 25 × 24×23× 22×..... ×2×1.
Answer:
Social Engineering
Explanation:
Even if you invest in the best possible security infrastructure for your corporate network, you will still be vulnerable to attacks which exploit human shortcomings. An example is where an attacker manipulates a company employee to get the system access password in return for a favour. Now he can use the password to bypass all security infrastructure and gain access to critical data and code.
FTP (File Transfer Protocol) can be used for a variety of tasks. For instance, webmasters using FTP for pushing updates/files to their websites can provide easy and straightforward changes to their services without the need to physically transfer files onto the host server. FTP should be used when you must update a file or files on a host server for a variety of reasons and you do not have access to the host server physically. However, FTP also has some inherent security risks which is why some webmasters/hosts chose to opt out of pushing updates through FTP in favour of physical file transfer.
Answer:
//""Print results to screen""
Explanation:
In c,c++,java,javascript // is used for the single line comment.
syntax:- // comment.
Whatever text that is followed after // is commented means this line will not get executed by the compiler.
Comments are used to explain the code to other person who is working on the code or trying to understand that code.
Here is a somewhat cryptic solution that works:
#include <algorithm>
#include <cstdlib>
using namespace std;
void q(char c, int count)
{
for (int i = 0; i < count; i++) {
putchar(c);
}
}
void p(int b1, int plusses)
{
q(' ', b1);
q('+', plusses);
}
int main()
{
for (int i = -3; i <= 3; i++)
{
int pl = min(6, (3 - abs(i)) * 2 + 1);
p(6-pl, pl);
i == 0 ? p(0, 6) : p(6, 0);
p(0, pl);
putchar('\n');
}
getchar();
}
