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lisabon 2012 [21]
3 years ago
15

2b

" 2 b^{2} -26b+80=0??" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
Factor out it by 2.
2(b² - 13b + 40) = 0
b<span>²</span> - 13b + 40 =0
This equation can be solved using the quadratic formula. If you know what a quadratic formula is, then you can get the two values for b. For instance,
(b - 8)(b - 5) = 0

Separate the two "roots", you will get:
b - 8 = 0
b = 8
and
b - 5 = 0
b = 5

Therefore the two values of b are 8 and 5.
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The standard form: Ax + By = C.

The point-slope form:

y-y_1=m(x-x_1)

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y-0=4(x-(-3))\\\\y=4(x+3)\qquad|\text{use distributive property}\\\\y=(4)(x)+(4)(3)\\\\y=4x+12\qquad|-4x\\\\-4x+y=12\qquad|\text{change the signs}\\\\\boxed{4x-y=-12}


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Answer:

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