Answer:
Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is 
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using = tank of gas.
The car can complete 1 trip by using = 
=
= 
= tank of gas
Thus, tank of gas used for each complete trip to Ottawa.
Answer:
this question is not complete. need another equation
Step-by-step explanation:
give another equation then I can solve
Dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.
<h3>What is dilation?</h3>
Dilation is a transformation, which is used to resize the object. Dilation is used to make the objects larger or smaller.
Here, △ HIJ are:
IH = 3
IJ = 4
then using the scale factor = 1/2 we get
Therefore, we have:
I'H '= 1.5
I'J '= 2
Hence, dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.
Learn more about this concept here:
brainly.com/question/1011146
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60 hundreds = 60 * 100 = 6,000 ( six thousands )
10 * 600 = 6,000 ( 10 times as many as 600 is 6,000 - six thousands )
Answer:
10 times as many as 6 hundreds is 60 hundreds or 6 thousands.
Answer:
6(3-2)
Step-by-step explanation:
Find the GCF of both numbers. The GCF is 6. Write it as 6( - )
Then, divide both numbers by 6. 18 divided by 6 is 3 and 12 divided by 6 is 2. Fill in the blanks with 3 and 2. A=6(3-2)
