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3 years ago

11

a rectangular yoga studio has an area of 153 square feet the width of the studio is nine feet. what is the lenghth of the studio

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1 answer:

daser333 [38]3 years ago

6 0

The length is 17 feet

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10 y is directly proportional to the cube of x. Given that y = 1512 when x = 6, find the equation for the y in terms of x.

sergiy2304 [10]

Answer:

${ \tt{y \: \alpha \: {x}^{3} }} \\ { \tt{y = k {x}^{3} }} \\ { \bf{k \: is \: a \: proportionality \: constant}} \\ { \tt{1512 = (k \times {6}^{3}) }} \\ { \tt{k = 7}} \\ { \boxed{ \bf{y = 7 {x}^{3} }}}$

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3 years ago

barxatty [35]

it would depend how much you actually used, but you would take the amount you used and divide it by the total amount of yarn. so if the yarn was 4m long and you used 2m then it would be 2/4 which is 0.5 which is also 50%, so half the yarn was used.

3 0

3 years ago

Assume that we have m coins. We toss each one of them n times. The probability of heads showing up for each coin isp. What’s the

olga nikolaevna [1]

Answer:

$1-(1-p^n)^m$

Step-by-step explanation:

For a coin, the probability of head showing in a single toss is $p$ .

$P(H)=p$

Its complement, the probability of not head is

$P(\Sim H)=1-p$

This is a binomial distribution. In $n$ tosses, the probability of having all heads (i.e. $n$ heads) is

$P(\text{all heads})=\binom{n}{n}p^n(1-p)^0=p^n$

Let's call this value $a$ .

For $m$ coins, we determine the probability of at least 1 coin showing all heads by first finding its complement i.e. the probability of no coin showing all heads. This is also a binomial distribution.

$P(\text{no coin showing all heads})=\binom{m}{0}a^0(1-a)^m=(1-a)^m$

$P(\text{at least 1 coin showing all heads})=1-P(\text{no coin showing all heads})$

$P(\text{no coin showing all heads})=1-(1-a)^m=1-(1-p^n)^m$

8 0

4 years ago

Juanita has a strip of paper divided into 8 equal sections. She colored 3 of the sections yellow, 2 of the sections black, and t

Musya8 [376]

I think its 2/8 but I'm not sure

5 0

4 years ago

The populations of two cities after t years can be modeled by -150t+50,000 and 50t+75,000 . What is the difference in the popula

creativ13 [48]

Answer:

The difference in the populations of the cities when t=4 is 25,800.

Step-by-step explanation:

Given equations each of the city:

-150t+50,000

and

50t+75,000

To find the difference between the population when t=4, we first have to solve both equation when t=4.

For both equations, substitute 4 into t:

-150(4) + 50,000 = 49,400

50(4) + 75,000 = 75,200

Now subtract 49,400 from 75,200 and you get 25,800.

The difference in the populations of the cities when t=4 is 25,800.

3 0

2 years ago

Read 2 more answers