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4 years ago

6

Do you have to take statistics in college

1 answer:

Alenkasestr [34]4 years ago

3 0

No you dont if you dont want ..

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In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at

DedPeter [7]

Answer:

5,31,616 bacteria

Step-by-step explanation:

Solution:

Here, Principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time (n) = 2 hours

After 2 hours, number of bacteria,

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+100R)n

= 506000\left(1+\frac{2.5}{100}\right)^2506000(1+1002.5)2

= 506000\left(1+\frac{25}{1000}\right)^2506000(1+100025)2

= 506000\left(1+\frac{1}{40}\right)^2506000(1+401)2

= 506000\left(\frac{41}{40}\right)^2506000(4041)2

= 506000\times\frac{41}{40}\times\frac{41}{40}506000×4041×4041

= 5,31,616.25

Hence, number of bacteria after two hours are 531616 (approx.).

5 0

3 years ago

If you currently have a (7) in your hand and you were to add two more cards to that (7), but the total sum of the cards is still

Molodets [167]

Answer:

king, queen, jack, ace

Step-by-step explanation:

this depends on what game's rules and scoring you're using, but I'd say the face cards

6 0

3 years ago

Someone please help me with problem #7 !!!

ser-zykov [4K]

Answer: b and d

Step-by-step explanation:

Since the roots are x=2 and x=6, we can write the equation as

$f(x)=a(x-2)(x-6)$

Substituting in the coordinates of the vertex,

$-4=a(4-2)(4-6)\\\\-4=-4a\\\\a=1$

So, the equation is $f(x)=(x-2)(x-6)$

On expanding, we get $f(x)=x^2 - 8x+12$

3 0

2 years ago

Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago

Find the value of x in the triangle shown below

Paul [167]

Pythagorean theorem:
$\sqrt{8 {}^{2} + 6 {}^{2} }$
$\sqrt{64 + 36}$
$\sqrt{100}$
$10$

6 0

3 years ago