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Kazeer [188]
3 years ago
5

I need to know this answer to this question "Compare 7 in 473?"

Mathematics
1 answer:
lesya [120]3 years ago
3 0
Just divide 7/473 you should get your answer

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15. What might explain the concern female students expressed in the beginning of this lesson about the problem of assigning prac
yanalaym [24]

Answer:

Interestingly, the likelihood of a randomly chosen student being a female is <u><em>0.58</em></u> at this school.

Step-by-step explanation:

This school features more female students than male students. <em>Consequently, if resources are allocated equally (because it has been found that both female and male male students are similarly likely to be involved), the number of female students involved in after-school athletics programs is greater than the number of male students and could clarify the facilities issues.</em>

3 0
3 years ago
According to the data in the figure, find the value of x and y.
drek231 [11]

Answer:

This is a educated guess, but x is 80 and y is 100.

Step-by-step explanation:

My logic here is that the triangles are the same because of all the congruent lines and stuff. But from there, you know that both the right and the left side are 40 degrees. You know the total degree of a triangle is 180 so 180 - 40 - 40 is 100. So the final angle is 100. If you look at x, its on the outside, but on a line. If you can imagine a circle, its half, so its a 180 degrees total. Then its 180 = x + 100. So x is 80. And then by that same logic its y = 100.

6 0
2 years ago
Larry fills his bathtub at a constant rate. The amount of water in his tub is proportional to the amount of time he spends filli
Kryger [21]

Answer:

7 but im not sure

Step-by-step explanation:

8 0
3 years ago
How did you get -1? In the problem xm=x+z ,for x
lys-0071 [83]
Remember, we can do anything to an equation as long as you do it to both sides

and distributive proeprty, reversed
ab+ac=a(b+c)

xm=x+z
minus x from both sides
xm-x=z
xm-1x
undistribute x
x(m-1)=z
divide both sides by (m-1)
x=\frac{z}{m-1}
3 0
3 years ago
a. esteban-perez and j. m. morales ´ , distributionally robust stochastic programs with side information based on trimmings, mat
sleet_krkn [62]

Distributionally robust stochastic programs with side information based on trimmings

This is a research paper whose authors are Adrián Esteban-Pérez and Juan M. Morales.

Abstract:

  • We look at stochastic programmes that are conditional on some covariate information, where the only knowledge of the possible relationship between the unknown parameters and the covariates is a limited data sample of their joint distribution. We build a data-driven Distributionally Robust Optimization (DRO) framework to hedge the decision against the inherent error in the process of inferring conditional information from limited joint data by leveraging the close relationship between the notion of trimmings of a probability measure and the partial mass transportation problem.
  • We demonstrate that our technique is computationally as tractable as the usual (no side information) Wasserstein-metric-based DRO and provides performance guarantees. Furthermore, our DRO framework may be easily applied to data-driven decision-making issues involving tainted samples. Finally, using a single-item newsvendor problem and a portfolio allocation problem with side information, the theoretical findings are presented.

Conclusions:

  • We used the relationship between probability reductions and partial mass transit in this study to give a straightforward, yet powerful and creative technique to expand the usual Wasserstein-metric-based DRO to the situation of conditional stochastic programming. In the process of inferring the conditional probability measure of the random parameters from a limited sample drawn from the genuine joint data-generating distribution, our technique generates judgments that are distributionally resilient to uncertainty. In a series of numerical tests based on the single-item newsvendor issue and a portfolio allocation problem, we proved that our strategy achieves much higher out-of-sample performance than several current options. We backed up these actual findings with theoretical analysis, demonstrating that our strategy had appealing performance guarantees.

To learn more about probability, visit :

brainly.com/question/11234923

#SPJ4

7 0
1 year ago
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