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dolphi86 [110]
3 years ago
9

A sample of Ar gas has a volume of 6.30 L with an unknown pressure. The gas has a volume of 8.57 L when the pressure is 2.74 atm

, with no change in temperature or amount of gas. What was the initial pressure, in atmospheres, of the gas?
Chemistry
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

3.73 atm

Explanation:

Since there is no change in temperature, we use Boyle's law.

P₁V₁ = P₂V₂ where P₁ = initial pressure of Ar gas = unknown, P₂ = final pressure of Ar gas = 2.74 atm, V₁ = initial volume of Ar gas = 6.30 L and V₂ = final volume of Ar gas = 8.57 L

P₁ = P₂V₂/V₁ = 2.74 atm × 8.57 L/6.30 L = 3.73 atm

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