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2 years ago

Use two points to enter an equation for the function. Give your answer in the form a (b^x). In the event

Mathematics

1 answer:

melomori [17]2 years ago

8 0

Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right, good luck, i tried to give you the right answer so if its wrong then its the system!

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

In the right triangle ABM

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

In the right triangle BMC

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

Find the length of DC

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

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3 years ago

What is the slope of a line perpendicular to the line whose equation is 6x+4y=-56

alex41 [277]

Answer:

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.Step-by-step explanation:

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2 years ago

A Russian mathmatician named Christian Goldbach came up with a theory that every even number can be written as the sum of two od

belka [17]

1 + 5 = 6
3 + 3 = 6

3 + 47 = 50
7 + 43 = 50
13 + 37 = 50
19 + 31 = 50

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2 years ago