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jonny [76]
3 years ago
10

The physical education instructor asked each student to do a total of 36 pull-ups and push-ups in 1 minute. The instructor wante

d students to do 8 times as many push-ups as pull-ups. Write a system of linear equations that represents this situation. How many pull-ups and push-ups were required in 1 minute?
Mathematics
1 answer:
NeTakaya3 years ago
8 0

Answer: Pull-ups = 4 and push up = 32

Step-by-step explanation:

Let x represents number of pull ups in one minute.

And, y represents number of push ups in one minute.

Therefore, According to the question,

Each student to do a total of 36 pull-ups and push-ups in 1 minute.

⇒ x+y= 36

But, again from equation, The instructor wanted students to do 8 times as many push-ups as pull-ups.

Therefore, 8x = y

Thus, required system of linear equations that represents this situation is,

x+y= 36 and 8x = y , where x is the number of pull ups and y is the number of push ups in one minute.

By solving these two equations we get, x=4 and y= 32

That is, In one minute 4 pull ups and 32 push ups are required.




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Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

2.50

Step-by-step explanation:

the pattern shown in the miles driven goes up each time by 5000, stating it's going up by a constant of 5000. the cost goes up each time by 2000.

divide 5000/2000 which would give you 2.5

round it by two decimal places which gives you 2.50

7 0
3 years ago
What is the perimeter of △ABC?
timofeeve [1]
<h3>Given</h3>
  • ΔABC
  • A(-3, -1), B(0, 3), C(1, 2)
<h3>Find</h3>
  • the length of the perimeter of ΔABC to the nearest tenth
<h3>Solution</h3>

The perimeter of a triangle is the sum of the lengths of its sides. The length of each side can be found using the Pythagorean theorem. Effectively, each pair of points is treated as the end-points of the hypotenuse of a right triangle with legs parallel to the x- and y-axes. The leg lengths are the differences betweeen the x- and y- coordinates of the points.

The difference of the x-coordinates of segment AB are 0-(-3) = 3. The y-coordinate difference is 3-(-1) = 4. So, the leg lengths of the right triangle whose hypotenuse is segment AB are 3 and 4. The Pythagorean theorem tells us

... AB² = 3² +4² = 9 +16 = 25

... AB = √25 = 5

You may recognize this as the 3-4-5 triangle often introduced as one of the first ones you play with when you learn the Pythagorean theorem.

LIkewise, segment AC has coordinate differences of ...

... C - A = (1, 2) -(-3, -1) = (4, 3)

These are the same leg lengths (in the other order) as for segment AB, so its length is also 5.

Segment BC has coordinate differences ...

... C - B = (1, 2) -(0, 3) = (1, -1)

The length of the line segment is figured as the root of the sum of squares, even though one of the coordinate differences is negative. The leg lengths of the right triangle used for finding the length of BC are the absolute value of these differences, or 1 and 1. Then the length BC is

... BC = √(1² +1²) = √2 ≈ 1.4

So the perimeter of the triangle ABC is

... AB + BC + AC = 5 + 1.4 + 5 = 11.4 . . . . perimeter of ∆ABC in units

_____

Please be aware that the advice to "round each step" is <em>bad advice,</em> in general. For real-world math problems, you only round the final result. You always carry at least enough precision in the numbers to ensure that there will not be any error in the final rounding.

In this problem, the only number that is not an integer is √2, so it doesn't really matter.

7 0
3 years ago
a conical tank with vertex down is 10 feet across the top and 12 feet deep. If water is flowing out of the tank at a rate of 12
TiliK225 [7]

Answer:

The water level is dropping at a rate of 0.24 ft/s

Step-by-step explanation:

Here, we simply want to calculate the change in depth (height of the cone) , given the volume change

Mathematically, we have the volume of a cone as;

V = 1/3 * π * r^2 * h

we are given dv/dt as 12 ft^3/m

dv/dh = 1/3 * π * r^2

Substituting the value for the radius, we have

dv/dh = 1/3 * 22/7 * 4^2 = 50.29

dh/dt = dh/dv * dv/dt

dh/dv = 1/(dv/dh) = 1/50.29

Thus,

dh/dt = 1/50.29 * 12

dh/dt = 0.24 ft/s

3 0
2 years ago
What is the height, h, of one of the triangles?<br> 4 ft<br> 8 ft<br> 7 ft<br> 14 ft
vagabundo [1.1K]

Answer:

4 ft

Step-by-step explanation:

the width of two triangles is given as 8 just divide by 2 since answer is asking for only one triangle

3 0
2 years ago
Read 2 more answers
20x^2/12x+8 simplified
shepuryov [24]
  1. 20/12 4
  2. 52/3
  3. 52+/3.+8

<h2 />

8 0
3 years ago
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