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Aleonysh [2.5K]
4 years ago
10

12.45 by 5 okokokookokokkok

Mathematics
1 answer:
jek_recluse [69]4 years ago
6 0

Answer:

<h3>.<u>=</u><u> </u><u>2</u><u>.</u><u>4</u><u>9</u></h3>

Step-by-step explanation:

hope that will help you

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Triangle A'B'C' is formed using the translation (x + 1. y + 1) and the dilation by a scale factor of 3 from the origin. Which eq
ArbitrLikvidat [17]

Answer:

d

Step-by-step explanation:

(x, y) ⇒ (x + 1, y +1) ⇒ (3x, 3y)

A (-3, 3) ⇒ A' (-2, 4) ⇒ A'' (-6, 12)

B (1, -3) ⇒ B' (2, -2) ⇒ B'' (6, -6)

C (-3, -3) ⇒ C' (-2, -2) ⇒ C'' (-6, -6)

8 0
3 years ago
four fifths of a grocery stores fruit display is made of apples if 1/4 of the apples are red apples what fraction of the fruit d
grandymaker [24]
.2 would be red apples 
hope this helps 
brainlyist pls

5 0
4 years ago
Read 2 more answers
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

3 0
3 years ago
Given a≠±b and a^2−b^2/a+b =12, find a−b.
11Alexandr11 [23.1K]
\dfrac{a^2 - b^2}{a+b}  =  12

--------------------------------------------------
Factorise a² - b² :
--------------------------------------------------
\dfrac{(a+b)(a-b)}{a+b}  =  12

--------------------------------------------------
 Crossed out common factors, (x + a) :
--------------------------------------------------
a- b =  12
4 0
4 years ago
Read 2 more answers
Look at this graph:
amm1812

For the given graph , slope of the line is equal to  ( 1 / 2 ).

As given in the question,

Form the given graph,

Scale is given by,

On x-axis each unit of the graph represent 1 unit.

On y- axis each unit of the graph represent 1 unit.

Consider two coordinates from the line of the graph,

( x₁ , y₁ ) = ( 1, 2 )

( x₂ , y₂ ) = ( 3, 3 )

Slope of the line = ( y₂ - y₁ ) / ( x₂ - x₁ )

 Substitute the value in the formula of the slope we get,

Slope of the line = ( 3 - 2 ) / ( 3 - 1 )

⇒ Slope of the line = 1 / 2

Therefore, for the given graph , slope of the line is equal to  ( 1 / 2 ).

Learn more about slope here

brainly.com/question/3605446

#SPJ1

3 0
1 year ago
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