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2 years ago

Which congruency theorem can be used to prove that △ABD ≅ △DCA? SSS ASA SAS AAS

Mathematics

2 answers:

SIZIF [17.4K]2 years ago

6 0

SAS is your answer I just had this question

NISA [10]2 years ago

3 0

Answer:

SAS

Step-by-step explanation:

Given: Two triangles ΔABD and ΔDCA,

We have, AD=AD (common)

∠A=∠A (Given)

BA=CD (Sides opposite to equal angles are always equal)

With the SAS rule of congruency,

ΔABD≅ΔDCA

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"Bill’s nominal income in 1990 was $1,009 per month. The CPI had a value of 149 in 1990 and had a value of 192 in 2017. What is

Bas_tet [7]

Answer:

$677.18

Step-by-step explanation:

Data provided in the question:

Bill’s nominal income in 1990 = $1,009 per month

CPI value in the year 1990 = 149

CPI value in the year 2017 = 192

Now,

The Consumer price index ( CPI ) is given as :

CPI = $\frac{\textup{Cost of basket in the current year}}{\textup{Cost of basket in the base year}}\times100$

thus,

for the given case of year 1990

149 = $\frac{\textup{1,009}}{\textup{Real income in the year 1990}}\times100$

Real income in 1990 = $\frac{\textup{1,009}}{\textup{149}}\times100$

Real income in 1990 = $677.18

4 0

2 years ago

Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050

attashe74 [19]

The answer is mean = 13,027; median = 12,200; no mode

Let's rearrange values from the lowest to the highest:
11350, 12050, 12200, 13325, 16211

The mean is the sum of all values divided by the number of values:
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The median is the middle value. If there is an odd number of data, then the median is the value in the middle. In the data set 11350, 12050, 12200, 13325, 16211, the median (the middle value) is 12200

The mode is the value that occurs most frequently. Since none of the number does not occur most frequently, there is no mode.

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