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3 years ago

7

You randomly choose two shapes from the bag, with replacement. Find the probability of choosing a star and then a circle. Write

your answer as a fraction in simplest form.

1 answer:

vodka [1.7K]3 years ago

3 0

Answer:

1/3

Step-by-step explanation:

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Alchen [17]

The area of the triangle PQR is 17.6 square units.

Explanation:

Given that the sides of the triangle are PQ = 12 and PR = 3 and $m\angle P = 78^{\circ}$

We need to determine the area of the triangle PQR

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

$\text {Area}=\frac{1}{2} qr \sin P$

Substituting the values, we get,

$\text {Area}=\frac{1}{2}(12)(3) \sin 78$

Simplifying, we have,

$\text {Area}=\frac{1}{2}(36)(0.98)$

Multiplying the terms, we have,

$\text {Area}=\frac{35.28}{2}$

Dividing, we get,

$\text {Area}=17.64$

Rounding off to the nearest tenth, we have,

$Area=17.6$

Thus, the area of the triangle PQR is 17.6 square units.

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

2 years ago

A line passes through the origin and the point

beks73 [17]

Answer:

Y=4+8

Step-by-step explanation:

6 0

3 years ago

The U.S. Department of Housing and Urban Development (HUD) uses the median to report the average price of a home in the United

MatroZZZ [7]

Answer:

Step-by-step explanation:

given that the U.S. Department of Housing and Urban Development (HUD) uses the median to report the average price of a home in the United States.

We know that mean, median and mode are measures of central tendency.

Mean is the average of all the prices while median is the middle entry when arranged in ascending order.

Mean has the disadvantage of showing undue figure if extreme entries are there. i.e. outlier affect mean.

Suppose a price goes extremely high, then mean will fluctuate more than median.

So median using gives a reliable estimate since median gives the middle price and equally spread to other sides.

3 0

3 years ago

Which equation represents the general from circle w

aev [14]

$d. \: {x}^{2} + {y}^{2} - 4x - 6y - 3 = 0 \\ \\ x = 2 + \infty \sqrt{(y - 7)(y + 1)} 2 - \infty \sqrt{(y - 7)(y + 1)}$

8 0

3 years ago