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Vikentia [17]
3 years ago
11

What is the perimeter of this quadrilateral? (5,5) (2, 4) (4, 1) (6, 1)

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

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Answer:

Step-by-step explanation:

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y = (-8/5)x + 4

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slope of any perpendicular to the line is ⅝.

line of slope ⅝ that passes through P(4,5):

y-5 = ⅝(x-4)

y = ⅝x + 2.5

find intersection of lines

⅝x + 2.5 = (-8/5)x + 4

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89x = 60

x = 60/89, y = 260/89

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3 years ago
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kogti [31]

Answer:

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Step-by-step explanation:

separate common terms and add them

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6 0
4 years ago
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vovikov84 [41]

Answer:

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Step-by-step explanation:

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Please help<br><br>answer choices are:<br><br>A. 46°<br><br>B. 67°<br><br>C. 115°<br><br>D. 134°​
bekas [8.4K]

Answer:

134°

Step-by-step explanation:

∠BAC = ∠BCA because it is an isosceles triangle

∠XCA = ∠XAC .  Congruent angles

∠XAC = 1/2(46) = 23° .  because CE bisects ∠ C

∠XCA = 23°

180° - 23° - 23° = 134° .  Sum of all angles in a triangle is 180°

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3 years ago
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jasenka [17]

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Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°

180-100=∠2

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The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.

80=9x-1

81=9x

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