If you are solving for a: it equals 3
distribute: 5a + 5=2a +14
get rid of extra number on one side: 5a=2a +9 (subtract 5 from both sides)
get rid of the other variable: 3a=9 (subtract 2a from both sides)
divide to isolate a: 3a/3=9/3 (divide by three on both sides)
answer= a=3
Answer:
Area of triangle ABC=7 square units
Area of triangle A'B'C'=7 square units
Step-by-step explanation:
Triangle ABC is the preimage of triangle A'B'C' under a reflection in the line x=0.
The two triangles are congruent so they have the same area.
We can calculate the area by counting the unit squares the triangle covered.
Each full box is 1 units square.
Each triangle covered
1 full box and 12 partially covered boxes.
Each partial box covered is 0.5 square units.
Therefore the area is
![Area=1+0.5\times12](https://tex.z-dn.net/?f=Area%3D1%2B0.5%5Ctimes12)
![Area=1+6](https://tex.z-dn.net/?f=Area%3D1%2B6)
square units
They are equal because if you divide 4÷1.0 your answer would be 0.4
Answer:
y= 1/2x+2
Step-by-step explanation:
Plug the slope and coordinates into point slope form y-1=1/2(x+2) and solve.