The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
Answer:The answer would be A. 1 1/5
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
Hope this helps!
Step-by-step explanation:
We have
(a + b)² = a² + 2ab + b²
so that with a = x² and b = 5, we have
x⁴ + 10x² + 25 = (x² + 5)²
Next, we have
a² - b² = (a - b) (a + b)
so that with a = x and b = √5 i,
x² + 5 = x² - (-5) = (x - √5 i) (x + √5 i)
So, the complete factorization over the complexes is
(x - √5 i)² (x + √5 i)²
Answer:
C?
Step-by-step explanation:
Answer:
$1500
6% interest
use the formula...
P(1+(r/100))^n
where P=initial amount
r=interest rate
t=time period elapsed
so ... for 5 years we get
$1500(1+(6/100))^5 = $1500(1.06)^5 = 2007.3383664
for 10 years
1500(1.06)^10 = 2686.271544814228043264
468 months = 39 years
1500(1.06)^39=14555.261231781943250017719606544
