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photoshop1234 [79]
3 years ago
7

If ∠G measures 45°, ∠F measures 82°, and f is 7 feet, then find g using the Law of Sines. Round your answer to the nearest foot.

triangle EFG with side e across from angle E, side f across from angle F, and side g across from angle g 4 ft 5ft 6ft 7ft
Mathematics
2 answers:
Alik [6]3 years ago
5 0

Answer:

probably 5 feet but not sure maybe so

Step-by-step explanation:

dsp733 years ago
3 0

Answer:

5 ft

Step-by-step explanation:

we know that

Applying the law of sines

\frac{f}{sin(F)}=\frac{g}{sin(G)}

substitute the given values

\frac{7}{sin(82^o)}=\frac{g}{sin(45^o)}

solve for g

g=\frac{7}{sin(82^o)}sin(45^o)=5\ ft

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Explain hovevou could estimate 22% of 78 to check if your answer is reasonable.
fomenos

Answer:

78 rounds to 80, so find 10% of 80 and double it. 10% of 80 is 8. So, 20% of 80 is 16. Then, 22% of 78 is a little more than 16.

78 rounds to 80, and 22% is a little less than 25%. 25% (or one-fourth) of 80 is 20. So, 22% of 78 is a little less than 20.

Step-by-step explanation:

8 0
3 years ago
Ayooo guys SOMEONE TELL ME WHAT IS THE AWNSER ?
Luden [163]

Answer:

60.......

Explanation:

7 0
2 years ago
find two positive real numbers such that they sum to 108 and the product of the first times the square of the second is a maximu
topjm [15]

The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.

Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.

Let us consider the two positive real numbers as x and y. Then, their sum is written as,

x+y=108

Then, y=108-x

And the product is written as,

P=xy²

Substitute value of y in the above equation, we get,

\begin{aligned}P&=x(108-x)^2\\&=x(11664-216x+x^2)\\&=11664x-216x^2+x^3\\&=x^3-216x^2+11664x\end{aligned}

Now, differentiate P with respect to x, and we get,

\begin{aligned}\frac{dP}{dx}&=3x^2-432x+11664\\&=x^2-144x+3888\end{aligned}

Solving the above equation to zero, we get,

\begin{aligned}x^2-144x+3888&=0\\x^2-36x-108x+3888&=0\\x(x-36)-108(x-36)&=0\\(x-108)(x-36)&=0\\x&=\text{108 or 36}\end{aligned}

Substitute values of x in y=108-x, to get values of y.

If we substitute x=108, we get the y value as zero which doesn't give the required solution.

But, if we substitute x=36, we get,

\begin{aligned}y&=108-36\\y&=72\end{aligned}

Thus, the two positive numbers are 36 and 72.

To know more about positive numbers:

brainly.com/question/1635103

#SPJ4

4 0
1 year ago
Given the line below.
Yanka [14]

We have to write the equation of the line, in point-slope form. Given an identified point (x1, y1) as the point (-2, 2). So that means x1=-2 and y1=2

Value of slope "m" is not given so i will keep using "m" for the slope. In case value of slope m is given in the problem then you can plug that number in place of m.

Point slope formula is given by:

y-y_1=m\left(x-x_1\right)

plug the given values into above formula :


y-\left(2\right)=m\left(x-\left(-2\right)\right)

y-2=m\left(x+2\right)

so the required answer in point slope form is y-2=m\left(x+2\right)

8 0
4 years ago
The coordinates of the vertices of △JKL are J(3, 4), K(3, 1) , and L(1, 1) . The coordinates of the vertices of △J′K′L′ are J′(−
timurjin [86]

The <em><u>correct answer</u></em> is:

A 180° rotation followed by a translation 1 unit down.

Explanation:

The points are mapped as follows:

J(3, 4)→J'(-3, -5)

K(3, 1)→K'(-3, -2)

L(1, 1)→L'(-1, -2)

A 180° rotation maps a point (x, y) to (-x, -y).  This would map

J(3, 4)→(-3, -4)

K(3, 1)→(-3, -1)

L(1, 1)→(-1, -1)

The difference between these points and the image points are that each y-coordinate of the image is 1 lower than these.  This means a translation 1 unit down would result in the image points.

7 0
3 years ago
Read 2 more answers
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